Optimal. Leaf size=168 \[ -\frac{f \text{CosIntegral}\left (\frac{2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac{2 c f}{d}\right )}{a d^2}-\frac{i f \text{CosIntegral}\left (\frac{2 c f}{d}+2 f x\right ) \cos \left (2 e-\frac{2 c f}{d}\right )}{a d^2}+\frac{i f \sin \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (2 x f+\frac{2 c f}{d}\right )}{a d^2}-\frac{f \cos \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (2 x f+\frac{2 c f}{d}\right )}{a d^2}-\frac{1}{d (c+d x) (a+i a \tan (e+f x))} \]
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Rubi [A] time = 0.239729, antiderivative size = 168, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {3724, 3303, 3299, 3302} \[ -\frac{f \text{CosIntegral}\left (\frac{2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac{2 c f}{d}\right )}{a d^2}-\frac{i f \text{CosIntegral}\left (\frac{2 c f}{d}+2 f x\right ) \cos \left (2 e-\frac{2 c f}{d}\right )}{a d^2}+\frac{i f \sin \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (2 x f+\frac{2 c f}{d}\right )}{a d^2}-\frac{f \cos \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (2 x f+\frac{2 c f}{d}\right )}{a d^2}-\frac{1}{d (c+d x) (a+i a \tan (e+f x))} \]
Antiderivative was successfully verified.
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Rule 3724
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{1}{(c+d x)^2 (a+i a \tan (e+f x))} \, dx &=-\frac{1}{d (c+d x) (a+i a \tan (e+f x))}-\frac{(i f) \int \frac{\cos (2 e+2 f x)}{c+d x} \, dx}{a d}-\frac{f \int \frac{\sin (2 e+2 f x)}{c+d x} \, dx}{a d}\\ &=-\frac{1}{d (c+d x) (a+i a \tan (e+f x))}-\frac{\left (i f \cos \left (2 e-\frac{2 c f}{d}\right )\right ) \int \frac{\cos \left (\frac{2 c f}{d}+2 f x\right )}{c+d x} \, dx}{a d}-\frac{\left (f \cos \left (2 e-\frac{2 c f}{d}\right )\right ) \int \frac{\sin \left (\frac{2 c f}{d}+2 f x\right )}{c+d x} \, dx}{a d}+\frac{\left (i f \sin \left (2 e-\frac{2 c f}{d}\right )\right ) \int \frac{\sin \left (\frac{2 c f}{d}+2 f x\right )}{c+d x} \, dx}{a d}-\frac{\left (f \sin \left (2 e-\frac{2 c f}{d}\right )\right ) \int \frac{\cos \left (\frac{2 c f}{d}+2 f x\right )}{c+d x} \, dx}{a d}\\ &=-\frac{i f \cos \left (2 e-\frac{2 c f}{d}\right ) \text{Ci}\left (\frac{2 c f}{d}+2 f x\right )}{a d^2}-\frac{f \text{Ci}\left (\frac{2 c f}{d}+2 f x\right ) \sin \left (2 e-\frac{2 c f}{d}\right )}{a d^2}-\frac{f \cos \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (\frac{2 c f}{d}+2 f x\right )}{a d^2}+\frac{i f \sin \left (2 e-\frac{2 c f}{d}\right ) \text{Si}\left (\frac{2 c f}{d}+2 f x\right )}{a d^2}-\frac{1}{d (c+d x) (a+i a \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 0.766762, size = 224, normalized size = 1.33 \[ \frac{\sec (e+f x) \left (\cos \left (\frac{c f}{d}\right )+i \sin \left (\frac{c f}{d}\right )\right ) \left (-2 f (c+d x) \text{CosIntegral}\left (\frac{2 f (c+d x)}{d}\right ) \left (\cos \left (e-\frac{f (c+d x)}{d}\right )-i \sin \left (e-\frac{f (c+d x)}{d}\right )\right )+2 f (c+d x) \text{Si}\left (\frac{2 f (c+d x)}{d}\right ) \left (\sin \left (e-\frac{f (c+d x)}{d}\right )+i \cos \left (e-\frac{f (c+d x)}{d}\right )\right )+d \left (-\sin \left (f \left (x-\frac{c}{d}\right )+e\right )+\sin \left (f \left (\frac{c}{d}+x\right )+e\right )+i \cos \left (f \left (x-\frac{c}{d}\right )+e\right )+i \cos \left (f \left (\frac{c}{d}+x\right )+e\right )\right )\right )}{2 a d^2 (c+d x) (\tan (e+f x)-i)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.171, size = 96, normalized size = 0.6 \begin{align*} -{\frac{1}{2\,ad \left ( dx+c \right ) }}-{\frac{f{{\rm e}^{-2\,i \left ( fx+e \right ) }}}{2\,a \left ( dfx+cf \right ) d}}+{\frac{if}{a{d}^{2}}{{\rm e}^{{\frac{2\,i \left ( cf-de \right ) }{d}}}}{\it Ei} \left ( 1,2\,ifx+2\,ie+{\frac{2\,i \left ( cf-de \right ) }{d}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.31302, size = 162, normalized size = 0.96 \begin{align*} -\frac{8 \, f^{2} \cos \left (-\frac{2 \,{\left (d e - c f\right )}}{d}\right ) E_{2}\left (\frac{2 i \,{\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) + 8 i \, f^{2} E_{2}\left (\frac{2 i \,{\left (f x + e\right )} d - 2 i \, d e + 2 i \, c f}{d}\right ) \sin \left (-\frac{2 \,{\left (d e - c f\right )}}{d}\right ) + 8 \, f^{2}}{16 \,{\left ({\left (f x + e\right )} a d^{2} - a d^{2} e + a c d f\right )} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.8012, size = 212, normalized size = 1.26 \begin{align*} \frac{{\left ({\left ({\left (-2 i \, d f x - 2 i \, c f\right )}{\rm Ei}\left (\frac{-2 i \, d f x - 2 i \, c f}{d}\right ) e^{\left (\frac{-2 i \, d e + 2 i \, c f}{d}\right )} - d\right )} e^{\left (2 i \, f x + 2 i \, e\right )} - d\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{2 \,{\left (a d^{3} x + a c d^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.44177, size = 797, normalized size = 4.74 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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